13.2x+x^2=125.44

Solution for 13.2x+x^2=125.44 equation:

13.2x+x^2=125.44

We move all terms to the left:

13.2x+x^2-(125.44)=0

We add all the numbers together, and all the variables

x^2+13.2x-125.44=0

a = 1; b = 13.2; c = -125.44;
Δ = b2-4ac
Δ = 13.22-4·1·(-125.44)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13.2)-26}{2*1}=\frac{-39.2}{2}
=-19+1/1.6666666666667
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13.2)+26}{2*1}=\frac{12.8}{2}
=6+0.8/2
$